In axapta 2012 all the common forms are listpage forms , In list page form we can’t override any method so any validation can be done through ListpageInteraction Class .
My intention is open the Listpage form from another form, so for that we need to change the code in InitializeQuery method of ListpageInteraction class.
1) Override the clicked method of menuitembutton of Calling form
ex:
FormRun formRun;
Args args = New Args();
super()
args.name(EAMWorkRequestListPage);
args.parmEnum(EAMWorkstatus::WaitingForAuthorization);
formRun = ClassFactory.formRunclass(args);
formRun.init();
formRun.run();
formRun.wait()
2) Based on passing enumvalue the Listpage will be filtered by overriding the InitializeQuery method of ListpageInteraction class.
if(this.listPage().listPageArgs() && this.listPage().listPageArgs().enumParameter())
{
status = this.listPage().listPageArgs().enumParameter();
qbds = _query.dataSourceTable(tableNum(EAMWorkRequest));
qbds.addRange(fieldNum(EAMWorkRequest,Status)).value(queryValue(status));
}
注意：PageList窗体中的MenuItemButton、Button控件只有当其“DisplayTarge”属性设置为“Client”时才能添加事件代码，但同时该按钮将无法部署并显示到EP页面。
原文地址(GFW)：http://axhelpdesk.blogspot.com/2013/06/open-listpage-form-from-another-form-by.html
原文地址(GFW)：http://axhelpdesk.blogspot.com/2013/06/open-listpage-form-from-another-form-by.html
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